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JIPMER2019PhysicsWaves and Sound

Find the distance between two consecutive nodes, if for a string T =0.25 ~N , =1 mg / m f =250 ~Hz .

Options

  1. A2 m
  2. B1 m
  3. C3 m
  4. D1.5 m

Correct answer

B. 1 m

Step-by-step solution

Given, Tension in the string, T =0.25 ~N a mass per unit length, =1 mg / m =10⁻⁶ ~kg / m Velocity of wave, v= T H (i) The distance between two consecutive nodes is equal to half the wave length ' '. v=f (ii) Form Eqs. (i) and (ii), aligned f = T m & = 1 f T = 1 250 0.25 10⁻⁶ & =2 aligned Difference between two consecutive nodes = 2 = 2 2 =1 ~m

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