JIPMER2006PhysicsWaves and Sound
There are 26 tuning forks arranged in the decreasing order of their frequencies. Each tuning fork gives 3 beats with the next. The first one is octave of the last. What is the frequency of 18 th tuning fork?
Options
- A100 Hz
- B99 Hz
- C96 Hz
- D103 Hz
Correct answer
B. 99 Hz
Step-by-step solution
Each tuning forck gives 3 beats with the next, so the difference in the frequencies of two consecutive forks is 3 . aligned f₂₆ & =f₁+(n-1) -3 f & =2 f+(26-1) -3 f & =75 ~Hz . aligned Frequency of 18 th tuning fork aligned f₁₈ & =f₁+(18-1) -3 & =2 75+17 -3 & =150-51=99 ~Hz aligned