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KCET2011ChemistryChemical Kinetics

The activation energy of a reaction at a given temperature is found to be 2.303 R T ~J ~mol ⁻¹ . The ratio of rate constant to the Arrhenius factor is

Options

  1. A0.01
  2. B0.1
  3. C0.02
  4. D0.001

Correct answer

B. 0.1

Step-by-step solution

k=A e^ -E_ a / R T aligned k A &=e^ -E_ a / R T ( k A ) &= -E_ a R T 2.303 ( k A ) &= -E_ a R T ( k A ) &= -E_ a 2.303 R T ( k A ) &= -2.303 R T 2.303 R T ( k A ) &=-1 k A &=0.1 aligned

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