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KCET2010ChemistryChemical Kinetics

The activation energy for a reaction at the temperature T ~K was found to be 2.303 RT J mol ⁻¹ . The ratio of the rate constant to Arrhenius factor is

Options

  1. A10⁻¹
  2. B10⁻²
  3. C2 10⁻³
  4. D2 10⁻²

Correct answer

A. 10⁻¹

Step-by-step solution

Arrhenius equation is, rate constant, aligned & k =A e ^ - E _ a / RT & k = Ae ^ -2.303 RT / RT & k A = e ^ -2.303 aligned On solving, we get k A =10⁻¹

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