KCET2014ChemistryCoordination Compounds
For ( Cr ₂ O ₇ ²⁻+14 H ⁺+6 e⁻ 2 Cr ³⁺+7 H ₂ O ; E ^ =1.33 ~V At [ Cr ₂ O ₇ ²⁻ ]=4.5 ) millimole, ( [ Cr ³⁺ ]=15 ) millimole, ( E ^ ) is ( 1.067 ~V ). The ( pH ) of the solution is nearly equal to
Options
- A( 03 )
- B( 04 )
- C( 12 )
- D( 05 )
Correct answer
C. ( 12 )
Step-by-step solution
( Cr ₂ O ₇ ²⁻+16 H ⁺+6 e⁻ 2 Cr ³⁺+7 H ₂ O ) ( E_ cell =E_ cell ^ + 0.0591 6 [ Cr ₂ O ₇ ²⁻ ] [ H ⁺ ]⁴ [ Cr ⁺³ ]² ) ( 1.067=1.33+ 0.0591 6 ( [ Cr ₂ O ₇ ²⁻ ] [ Cr ³⁺ ]²+ [ H ⁺ ]¹⁴ ) ) ( 1.067-1.33= 0.0591 6 - (- [ Cr ₂ O ₇ ²⁻ ] [ Cr ⁺³ ]² - [ H ⁺ ]¹⁴ ) ) ( -0.263= -1 100 (- (4.5 10⁻³ ) (15 10⁻³ )² +14 p H ) ) ( 26.3= 1 20 +14 p H ) ( 26.3=-1.3010+14 p H ) ( 27.6=14 p H p H 2 )