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KCET2008Chemistryd and f Block Elements

When sulphur dioxide is passed in an acidified K ₂ Cr ₂ O ₇ solution, the oxidation state of sulphur is changed from

Options

  1. A+4 to 0
  2. B+4 to +2
  3. C+4 to +6
  4. D+6 to +4

Correct answer

C. +4 to +6

Step-by-step solution

Acidified K ₂ Cr ₂ O ₇ solution oxidises SO ₂ into Cr ₂ ( SO ₄ )₃ . aligned 3 SO ₂+ K ₂ Cr ₂ O ₇+& H ₂ SO ₄ K ₂ SO ₄ &+ Cr ₂ ( SO ₄ )₃+ H ₂ O aligned Hence, oxidation state of sulphur changes from +4 to +6 .

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