A current of 3 A is passed through a molten calcium salt for 1 hr 47 min 13 s . The mass of calcium deposited is (Molar mass of Ca =40 ~g ~mol ⁻¹ )

Step-by-step solution

Given, t=1 hr 47 ~min 13 sec =6433 seconds Molar mass of Ca =40 ~g / mol Current (i)=3 A Mass of calcium deposited (w)= ? Using Faraday's 2^ nd law w=z i t ....(i) where, z= M n 96500 = 40 2 96500 Substitute the value of Z and given values in equation (i) W= 40 3 6433 2 96500 =3.99 ~g 4 ~g