The resistance of 0.1 M weak acid H A in a conductivity cell is 2 10^3 Ohm . The cell constant of the cell is 0.78 C m ⁻¹ and _ m ^ of acid H A is 390 ~S ~cm ^2 ~mol ⁻¹ . The pH of the solution is

Step-by-step solution

Given, C=0.1 M aligned _ m ^ & =390 Scm ^2 ~mol ⁻¹ R & =2 10^3 ohm G^* & =0.78 ~cm ⁻¹ aligned Now, K= R G^ = 0.78 2 10^3 =3.9 10⁻⁴ aligned _ m ^ & = K 1000 C = 3.9 10⁻⁴ 1000 0.1 =3.9 & = _ m _ m ^ = 3.9 390 =10⁻² [ H ⁺ ] & =C =0.1 10⁻²=10⁻³ aligned So, pH =- 10⁻³=3