The amount of current in Faraday is required for the reduction of ( 1 ~mol ) of ( Cr ₂ O ₇ ²⁻ ) ions to ( C r³⁺ ) is,

Step-by-step solution

The balance reaction is, Cr ₂ O ₇²⁻+4 H ⁺+6 e⁻ 2 Cr ³⁺+7 H ₂ O From the reaction, 1 ~mol of Cr ₂ O ₇²⁻ requires 6 ~F to convert into Cr ³⁺ ion. Q = nF (where, n = no. of e⁻ ) Q=6 ~F