The equilibrium constant of the reaction A ( s )+2 ~B ²⁺( aq ) A ²⁺( aq )+2 ~B ( ~s ) F _ cell ^ =0.0295 ~V is [ 2.303 RT F =0.059 ]

Step-by-step solution

A ( s )+2 ~B ⁺( aq ) A ²⁺( aq )+2 ~B ( ~s ) ; Here, n = number of e ⁻ transfer =2 E _ cell ^ =0.295 ~V ~K _ c =? E _ cell ⁰= 0.059 n K _ c 0.0295= 0.059 2 K _ c K _ c =1= 10 K _ c =10