KCET2010ChemistryElectrochemistry
E ₁, E ₂, E ₃ are the emf values of the three galvanic cells respectively.
Options
- AE ₂> E ₃> E ₁
- BE ₃> E ₂> E ₁
- CE ₁> E ₂> E ₃
- DE ₁> E ₃> E ₂
Correct answer
B. E ₃> E ₂> E ₁
Step-by-step solution
For the given cell, E _ cell = E _ cell ^ - 0.0591 2 [ Zn ²⁺ ] [ Cu ²⁺ ] (i) aligned E ₁ &= E _ cell ^ - 0.0591 2 1 0.1 &= E _ cell ^ - 0.0591 2 aligned (ii) E ₂= E _ cell ^ - 0.0591 2 1 1 = E _ cell ^ - 0.0591 2 0 = E _ cell ^ (iii) E ₃= E _ cell ^ - 0.0591 2 0.1 1 = E _ cell ^ + 0.0591 2 E ₃> E ₂> E ₁