KCET2014Chemistrys Block Elements
A plot of ( 1 T Vs . k ) for a reaction gives the slope ( -1 10⁴ ~K . ) The energy of activation for the reaction is (Given ( R=8.314 J K⁻¹ ~mol ⁻¹ ) )
Options
- A( 1.202 ~kJ ~mol ⁻¹ )
- B( 83.14 ~kJ ~mol ⁻¹ )
- C( 8314 Jmol ⁻¹ )
- D( 12.02 ~J ~mol ⁻¹ )
Correct answer
B. ( 83.14 ~kJ ~mol ⁻¹ )
Step-by-step solution
Arrhenius equation, ( k=A e^ - E_ a R T (1) ) Taking natural log of Eq. (1), we get ( k= A- E_ a R 1 T ) By plotting In ( k ) against ( 1 / T ), a straight line with slope ( =- E R ) and intercept ( A ). Now, slope ( =- E_ a R ) ( -1 10⁴=- E_ a 8.314 ) ( E_ a =8.314 1 10⁴ ) ( E_ a =83.140 ~kJ ~mol ⁻¹ )