KCET2008Chemistrys Block Elements
-propyl bromide on treating with alcoholic KOH produces
Options
- Apropane
- Bpropene
- Cpropyne
- Dpropanol
Correct answer
B. propene
Step-by-step solution
Alcoholic KOH is a dehydrohalogenating reagent, so when -propyl bromide is treated with alcoholic KOH , propene is obtained. CH ₃ CH ₂ CH ₂ Br + alc KOH n-propyl bromide CH ₃ CH = Propene = CH ₂+ HBr