A pure compound contains 2.4 ~g of C , 1.2 10²³ atoms of H , 0.2 moles of oxygen atoms. Its empirical formula is

Step-by-step solution

Moles of carbon = w M = 2.4 12 =0.2 ~mol Moles of H in 1.2 10²³ atoms of H = 1.2 10²³ 6 10²³ =0.2 ~mol Moles of oxygen atoms =0.2 moles Now, simplest ratio of the moles of C , H and O is as follows aligned &= C : H : O &=0.2: 0.2: 0.2= CHO aligned Thus, the empirical formula of the compound is CHO.