A metal exists as an oxide with formula M_ 0.96 O . Metal, M can exist as M²⁺ and M³⁺ in its oxide M_ 0.96 O . The percentage of M³⁺ in the oxide is nearly

Step-by-step solution

We are given metal oxide with formula M_ 0.96 O . Here, M can exist as M²⁺ as well as M³⁺ . Here, for every 100 oxide ions there are 96 M ions. Let out of this 96 M atoms, M²⁺ exists =x and M³⁺ will be =(96-x) . Total positive charge on 96 M -atoms =2 x+3 (96-x) Total negative charge on 100 O -atoms =100 2=200 As per electrical neutrality concept aligned 2 x+3(96-x) &=200 2 x+288-3 x &=200 -x &=200-288 -x &=-88 or x=88 96-88 &=8 aligned So, the ratio of M³⁺ will be 8 96 100=8.3 %