In a series L C R circuit, R=300 , L=0.9 H , C=2.0 F and =1000 rad / s , then impedance of the circuit is

Step-by-step solution

Given, R=300 , L=0.9 H , =1000 rad / s C=2.0 F =2 10⁻⁶ ~F Impedance of given R-L-C circuit, aligned Z & = R^2+ (X_L-X_C )^2 & = R^2+ ( L- 1 C )^2 [ X_L= L and X_C= 1 C ] & = (300)^2+ (1000 0.9- 1 1000 2 10⁻⁶ )^2 & = 90000+(900-500)^2 & = 90000+160000 = 250000 =500 aligned