The minimum value of effective capacitance that can be obtained by combining ( 3 ) capacitors of capacitances ( 1 pF , 2 pF ) and ( 4 pF ) is

Step-by-step solution

The effective capacitance will be minimum when the threecapacitors are connected in series. The effective capacitance is given by [ array l array l C₁=1 pF C₂=2 pF C₃=4 pF 1 C_ e f f = 1 C₁ + 1 C₂ + 1 C₃ = 1 1 p F + 1 2 p F + 1 4 p F = (4+2+1) 4 p F = 7 4 Therefore C_ eff = 4 7 p F array array ]