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KCET2016PhysicsAlternating Current

A capacitor of ( 8 ~F ) is connected as shown. Charge on the plates of the capacitor

Options

  1. A( 32 ) C
  2. B( 40 C )
  3. C( 00 )
  4. D( ( 80 C )

Correct answer

A. ( 32 ) C

Step-by-step solution

Current through ( 4 ) resister is ( I= E R+r = 5 4+1 =1 A ) Thus, potential difference across ( 4 ) resistor is [ V=I R=1 A 4 =4 V ] Therefore, charge on the plate of capacitor is [ Q=C V=8 F 4 V=32 C ] Thus, charge ( =32 C )

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