KCET2010PhysicsAlternating Current
In a series resonant R-L-C circuit, the voltage across R is 100 ~V and the value of R =1000 . The capacitance of the capacitor is 2 10⁻⁶ ~F ; angular frequency of AC is 200 rad s ⁻¹ . Then the potential difference across the inductance coil is
Options
- A100 ~V
- B40 ~V
- C250 ~V
- D400 ~V
Correct answer
C. 250 ~V
Step-by-step solution
The current in the circuit aligned i &= V _ R R &= 100 1000 =0.1 ~A aligned At resonance, aligned V _ L &= V _ C = iX _ C = i C &= 0.1 200 2 10⁻⁶ &=250 ~V aligned