KCET2024PhysicsAtomic Physics
The ratio of volume of Al ²⁷ nucleus to its surfactarea is (Given, R₀=1.2 10⁻¹⁵ ~m )
Options
- A2.1 10⁻¹⁵ ~m
- B1.3 10⁻¹⁵ ~m
- C0.22 10⁻¹⁵ ~m
- D1.2 10⁻¹⁵ ~m
Correct answer
D. 1.2 10⁻¹⁵ ~m
Step-by-step solution
Volume of Al ²⁷ nucleus Surface area = 4 3 R^3 4 R^2 = R 3 = 1 3 (R₀ A^ 1 3 ) [ R=R₀ A^ 1 3 ]= 1 3 1.2 10⁻¹⁵(27)^ 1 3 =1.2 10⁻¹⁵ ~m