An electron in an excited state of Li ²⁺ ion has angular momentum 3 h 2 . The de-Broglie wavelength of electron in this state is p a₀ (where, a₀= Bohr radius ). The value of p is

Step-by-step solution

According to de-Broglie hypothesis, = n h 2 = 3 h 2 =m v r n=3 As, wavelength, = h p = h m v = h r m v r = h r 3 h = 2 3 r For Li ²⁺ atom, radius of orbit, r=r₀ n² Z =a₀ 3² 3 =3 a₀ = 2 3 a₀ 3=2 a₀=p a₀ (given) p=2