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KCET2020PhysicsAtomic Physics

The de-Broglie wavelength associated with electron of hydrogen atom in this ground state is

Options

  1. A0.3 Å
  2. B3.3 Å
  3. C6.26 Å
  4. D10 Å

Correct answer

B. 3.3 Å

Step-by-step solution

The angular momentum of electron in an orbit of radius r is, m v r= n h 2 So, momentum in ground state, p=m v= h 2 r ...(i) The de-Broglie wavelength associated with an electron is = h m v = h p =2 r [from Eq. (i)] As we know, in ground state of hydrogen atom, r=0.53 Å =2 0.53 Å=3.3 Å

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