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KCET2015PhysicsAtomic Physics

What is the wavelength of light for the least energetic photon emitted in the Lyman series of the hydrogen spectrum, (take hc ( =1240 eV mm ) )

Options

  1. A( 82 ~mm )
  2. B( 102 ~mm )
  3. C( 122 ~mm )
  4. D( 150 ~mm )

Correct answer

C. ( 122 ~mm )

Step-by-step solution

We know, ( 1 =R ( 1 n₁² - 1 n₂² ) ) For Lyman series, ( n₁=1 ) and ( n 2=2 ) is least energetic. Therefore, [ array l 1 =1.097 10⁷ ( 1 1² - 1 2² )=1.097 10⁷ ( 4-1 4 ) = 3 4 1.09 10⁷ array ] Thus ( = 4 3 1.097 10⁷ =122 ~nm )

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