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KCET2008PhysicsAtomic Physics

The ratio of minimum wavelengths of Lyman and Balmer series will be

Options

  1. A1.25
  2. B0.25
  3. C5
  4. D10

Correct answer

B. 0.25

Step-by-step solution

The series end of Lyman series corresponds to transition from n _ i = to n _ f =1 , corresponding to the wavelength aligned & 1 ( _ )_ L = R [ 1 1 - 1 ]= R ( _ )_ L &= 1 R =912 Å aligned For last line of Balmer series aligned & 1 ( _ )_ B =R [ 1 (2)² - 1 ( )² ]= R 4 & ( _ )_ B = 4 R =3636 Å aligned Dividing Eq. (i) by Eq. (ii), we get ( _ )_ L ( _ )_ B =0.25

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