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KCET2024PhysicsCapacitance

A capacitor of capacitance 5 ~F is charged by a battery of emf 10 V . At an instant of time, the potential difference across the capacitors is 4 V and the time rate of change of potential difference across the capacitor is 0.6 Vs ⁻¹ . Then, the time rate at which energy is stored in the capacitor at any instant is

Options

  1. A12 ~W
  2. B3 ~W
  3. CZero
  4. D30 ~W

Correct answer

A. 12 ~W

Step-by-step solution

Given, battery emf, e=10 ~V C=5 ~F =5 10⁻⁶ ~F V=4 ~V d V / d t=0.6 Vs ⁻¹ We know that stored energy, U= 1 2 C V^2 d U d t = 1 2 C 2 V d V d t =C V d V d t =5 10⁻⁶ 4 0.6=12 10⁻⁶ ~W =12 ~W

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