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KCET2022PhysicsCapacitance

A parallel place capacitor is charged by connecting a 2 ~V battery across it. It is then disconnected from the battery and a glass slab is introduced between plates. Which of the following pairs of quantities decrease?

Options

  1. APotential difference and energy stored
  2. BEnergy stored and capacitance
  3. CCapacitance and charge
  4. DCharge and potential difference

Correct answer

A. Potential difference and energy stored

Step-by-step solution

When a charged capacitor is disconnected from the battery and a glass slab (dielectric material) is introduced between the plates, then charge (Q), capacitance (C) , electric potential (V) and stored energy (U) is given as Q=Q₀, C=K C₀, V= V₀ K and U= U₀ K where, K= dielectric constant aligned V & = electric potential U & = potential energy V₀ & = initial potential of charged capacitor U₀ & = Initial energy of charged capacitor aligned From above, we see that V and U decreases after introducing glass plate of diele

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