KCET2021PhysicsCapacitance
An electrician requires a capacitance of 6 F in a circuit across a potential difference of 1.5 kV . A large number of 2 F capacitors which can withstand a potential difference of not more than 500 ~V are available. The minimum number of capacitors required for the purpose is
Options
- A3
- B9
- C6
- D27
Correct answer
D. 27
Step-by-step solution
Number of capacitors that can be connected in each row, aligned m &= Desired voltage Voltage across each capacitor &= 1.5 kV 500 ~V = 1500 500 =3 aligned Effective capacitance when m capacitors are connected in n rows is given as C_ eff = n C m array lc Here, m=3, C=2 F , C_ eff =6 F & n 2 3 =6 or & n= 18 2 =9 array Total number of capacitors required, N=m n=3 9=27 .