In figure, charge on the capacitor is plotted against potential difference across the capacitor. The capacitance and energy stored in the capacitor are respectively.

Step-by-step solution

Energy stored in a capacitor is given as U= 1 2 C V²...(i) where, C is the capacitance. From the given graph, we get Slope = = Q V = 120 C 10 ~V ...(ii) As we know, capacitance is given as C= Q V Substituting the value of Q V from Eq. (ii) in the above relation, we get aligned C &= 120 C 10 ~V = 120 10⁻⁶ 10 =12 10⁻⁶ ~F &=12 F aligned Now, substituting the values of C and V in Eq. (i), we get aligned U &= 1 2 12 (10)² &=600 J aligned