KCET2020PhysicsCapacitance
The difference between equivalent capacitances of two identical capacitors connected in parallel to that in series is 6 F . The value of capacitance of each capacitor is
Options
- A2 F
- B3 F
- C4 F
- D6 F
Correct answer
C. 4 F
Step-by-step solution
Given, C₁=C₂=C (identical capacitors) When both capacitors are connected in parallel, then equivalent capacitance aligned &C_ p =C₁+C₂=C+C &C_ p =2 C ...(i) aligned When both capacitors are connected in series, then equivalent capacitance, aligned 1 C_ s &= 1 C₁ + 1 C₂ = 1 C + 1 C 1 C_ s &= 2 C C_ s = C 2 aligned According to question, C_ p -C_ s =6 F 2 C- C 2 =6 F 3 C 2 =6 F C=4 F