The particles emitted in the decay of ( ₉₂²³⁸ U ) to ( ₉₂²³⁴ U ) :

Step-by-step solution

Given decay reaction is ₉₂²³⁸ U ₉₂ ²³⁴ U We know that, a-decay is z^ A X z-2^ A-4 Y+ - particle -decay is z^ A X z-1^ A X+ - particle In above decay of uranium, change in mass number A is 4 and change in atomic number Z is 0 . Change in mass number A implies number of a particles emitted is 1 . Now, emission of an a-particle implies atomic number reduces by 2 but there is no change in atomic number Therefore, number of particles emitted is 2 . Thus, the given reaction ₉₂²³⁸ U ₉₂²³⁴ U+1 +2 ⁻