KCET2009PhysicsCapacitance
The charge deposited on 4 F capacitor in the circuit is
Options
- A6 10⁻⁶ C
- B12 10⁻⁶ C
- C24 10⁻⁶ C
- D36 10⁻⁶ C
Correct answer
C. 24 10⁻⁶ C
Step-by-step solution
As the capacitors 4 F and 2 F are connected in parallel and are in series with 6 F capacitor, their equivalent capacitance is (2+4) 6 2+4+6 =3 F Charge in the circuit, Q =3 F 12 ~V =36 C Since, the capacitors 4 F and 2 F are connected in parallel, therefore potential difference across them is same. Q ₁ Q ₂ = C ₁ C ₂ = 4 2 or Q ₁=2 Q ₂ aligned & Also, Q₁=Q₁+Q₂ & 36 C=2 Q₂+Q₂ or Q₂= 36 C 3 =12 C &Q₁=Q-Q₂=36 C-12 C &=24 C=24 10⁻⁶ C aligned