The number of electrons moving per second through the filament of a lamp of 60 W operating at 120 V is nearly (e = 1.6 10⁻¹⁹ C ) _____________.

Step-by-step solution

Power of the lamp, P = 60 W Operating voltage, V = 120 V Current through the filament, I = P V = 60 120 = 0.5 A Let n be the number of electrons flowing per second. Then the current is given by I = ne , where e is the elementary charge. n = I e = 0.5 1.6 10⁻¹⁹ n = 5 16 10¹⁹ = 3.125 10¹⁸ The number of electrons moving per second is nearly 3.1 10¹⁸ . Answer: 3.1 10¹⁸