In a conducting region, 10¹⁹ electrons and 10¹⁹ protons move to the left, while 10¹⁹ -particles move to the right per second. The resulting electric current is (e = 1.6 10⁻¹⁹ C ) _________

Step-by-step solution

The electric current is given by the rate of flow of positive charge. The direction of current is the direction of flow of positive charge, and opposite to the direction of flow of negative charge. Current due to electrons moving left: I_e = n_e e = 10¹⁹ 1.6 10⁻¹⁹ = 1.6 A towards right. Current due to protons moving left: I_p = n_p e = 10¹⁹ 1.6 10⁻¹⁹ = 1.6 A towards left. Current due to -particles moving right: I_ = n_ (2e) = 10¹⁹ 2 1.6 10⁻¹⁹ = 3.2 A towards right. Taking the rightward direction as positive, the ne