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KCET2023PhysicsCurrent Electricity

Ten identical cells each emf 2 ~V and internal resistance 1 are connected in series with two cells wrongly connected. A resistor of 10 is connected to the combination. What is the current through the resistor?

Options

  1. A1.8 ~A
  2. B2.4 ~A
  3. C0.6 ~A .
  4. D1.2 ~A

Correct answer

C. 0.6 ~A .

Step-by-step solution

According to given situation, Net emf of the combination, E_ net =8 emf of one cell -2 emf of one cell =8 2-2 2=12 ~V Equivalent resistance of the circuit R^ =10 r+R=10 1+10=20 ~V Current through the resistor, I= E_ net R^ = 12 20 =0.6 ~A

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