A wire of a certain material is stretched slowly by 10 % . Its new resistance and specific resistance becomes respectively

Step-by-step solution

Let initial length of the wire be l . After stretching new length of the wire l^ is given as l^ =l+10 % of l=l+ 10 100 l= 11 l 10 =1 . l i.e. length is increased by 1.1 times n=1.1 We know that, when length of a wire is increased by n times, then its new resistance is increased by n^2 times i.e. R^ =n^2 R=(1.1)^2 R [ Here, n=1.1]=1.21 R Specific resistance (resistivity) of a wire does not depends on its dimensions (length, width etc.) because it is a characteristic property of a materia and depends only nature of m