Each resistance in the given cubical network has resistance of 1 and equivalent resistance between A and B is

Step-by-step solution

The given network of resistances can be shown as follows, Let 6 I be the current through the cell, which is distributed as shown in the figure. Applying Kirchhoff's law to the loop A B C C^ E A , we have E=5 I If R^ be the equivalent resistance of the network, then R^ = total emf total current = 5 I 6 I = 5 6