Masses of three wires of copper are in the ration ( 1: 3: 5 ) and their lengths are in the ratio ( 5: 3 ) : 1. The ratio of their electrical resistance are

Step-by-step solution

( (C) ) Resistance ( R = l A ) [ array l A= volume l = mass l Density = m l d R= s l m l d = s d l² m R l² m array ] [ array l R₁: R₂: R₃= l₁² m₁ : l₂² m₂ : l₃² m₃ = 5 l² m : 3 l² 3 m : l² 5 m =25: 3: 1 5 ( l m is a constant )=125: 15: 1 array ]