Five identical resistors each of resistance ( R=1500 ) are connected to a ( 300 ) battery as shown in the circuit. The reading if the ideal ammeter ( A ) is

Step-by-step solution

Given, ( R=1500 ; V=300 ~V ) Since the resistances are in parallel. The above circuit can be reduced to the circuit as follows: Thus, current through ammeter is ( I₂ ), given by [ I₂= V R = 300 R / 3 = 300 1500 / 3 = 300 500 = 3 5 ]