KCET2017PhysicsCurrent Electricity
The mass defect of ( ₂⁴ He ) is ( 0.03 u ). The binding energy per nucleon of helium (in ( MeV ) ) is
Options
- A( 27.93 )
- B( 6.9825 )
- C( 2.793 )
- D( 69.825 )
Correct answer
B. ( 6.9825 )
Step-by-step solution
Binding energy is the amount of energy required to separate a particle from a system of particles. It is given as ( B= ( m) c² A ) where ( m ) is the mass defect Given, mass defect ( m =0.03 u , A =4 ) Therefore, binding energy per nucleon of helium is ( B= 0.03 931 4 MeV =6.9825 MeV )