Three conductors draw currents of 1 ~A , 2 ~A and 3 A respectively, when connected in turn across a battery. If they are connected in series and the combination is connected across the same battery, the current drawn will be

Step-by-step solution

Let the three conductors are R₁, R₂ and R₃ and the current drawn by them 1 ~A , 2 ~A and 3 ~A respectively when connected in turn across a battery. V=R₁, V=2 R₂ and V=3 R₃ So, R₁=V, R₂= V 2 and R₃= V 3 When the conductors are connected in series, across the same battery, then array ll & V=l [R₁+R₂+R₃ ] & V=I [V+ V 2 + V 3 ] & 1=I [ 6+3+2 6 ] or & I= 6 11 ~A array