KCET2013PhysicsCurrent Electricity
In the circuit, R₁=R₂ . The value of E and R₁ are (E- EMF , R₁- . resistance )
Options
- A180 ~V , 60
- B120 ~V , 60
- C180 ~V , 10
- D120 ~V , 10
Correct answer
A. 180 ~V , 60
Step-by-step solution
Applying Kirchoff's 2nd law in loop A B E F A-I R-(I-1.5) R+E=0 or E=I R+(I-1.5) R E=R[2 l-1.5]...(i) Now apply KVL in loop A B C D E F A , array ll & -I R-1.5 R^ +E=0 & E=I R+1.5 R^ ...(ii) array Eliminating / from Equ. (i) and (ii), 1 2 [ E R +1.5 ]=1 [from Eq. (i)] and [ E-1.5 R^ R ]= । [from Eq. (ii)] So, E R +1.5= 2 R [E-1.5 R^ ]