In this circuit, when certain current flows, the heat produced in 5 is 4.05 ~J in a time t. The heat produced in 2 coil in the same time interval is

Step-by-step solution

Let, the current distribution is as shown, then by current divider rule, H₁= (6+9) (6+9)+5 I= 3 4 I Let H and H ₁ be heat produced in 2 and 5 resistors respectively in time t, then gathered H = I ²(2) t =2 I ² t and H ₁= I ₁²(5) t = II ₁² t = 45 16 I ² t H H _ I = 32 45 = 32 45 4.05 ~J =2.88 ~J gathered