KO ₂ , reacts with water to form A, B and C . B forms C when it reacts with iodine in basic medium. What are B and C respectively?

Step-by-step solution

(i) When KO ₂ reacts with water, it gives (A) , (B) and (C) as follows: (ii) When (B) , i.e. H ₂ O ₂ reacts with iodine in basic medium, it gives (C) , i.e. O ₂ , as shown below : KOH can not reduce I ₂ , thus option (d) is the correct answer.