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KCET2022PhysicsElectromagnetic Induction

A long solenoid has 500 turns, when a current of 2 ~A is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4 10⁻³ ~Wb , then selfinduction of the solenoid is

Options

  1. A2.5 H
  2. B2.0 H
  3. C1.0 H
  4. D4.0 H

Correct answer

C. 1.0 H

Step-by-step solution

Given, number of turns in the solenoid, N=500 Current, I=2 ~A Magnetic flux, =4 10⁻³ ~Wb Self-inductance of coil, L= N I = 500 4 10⁻³ 2 =1 H

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