KCET2018PhysicsElectromagnetic Induction
A charge ( q ) is accelerated through a potential difference ( V ). It is then passed normally through a uniform magnetic field, where it moves in a circle of radius ( r ). The potential difference required to move it in a circle of radius ( 2 r ) is
Options
- A( 12 ~V )
- B4V
- C( 1 ~V )
- D( 3 ~V )
Correct answer
B. 4V
Step-by-step solution
Given, charge q is accelerated through a potential difference V . Therefore, 1 2 m v²=q V m v²=2 q V (m v)²=2 q m V m v= 2 m q V The radius of circular path followed by the charge is r= m v q B = 2 m q V q B r V Thus, the potential difference required to move the charge in circle of radius 2 r is 4 ~V