An electron falls through a distance 1.5 cm in 2.0 10^4 N/C from rest. The time taken to cover this distance in second is ____ (e = 1.6 10⁻¹⁹ C , m_e = 9.11 10⁻³¹ kg )

Step-by-step solution

Force on the electron is F = eE Acceleration of the electron is a = eE m_e Using the equation of motion s = ut + 1 2 at^2 Since the electron starts from rest, u = 0 s = 1 2 ( eE m_e ) t^2 t = 2sm_e eE Substituting the given values: t = 2 1.5 10⁻² 9.11 10⁻³¹ 1.6 10⁻¹⁹ 2.0 10^4 t = 27.33 10⁻³³ 3.2 10⁻¹⁵ t = 8.54 10⁻¹⁸ t 2.9 10⁻⁹ s Answer: 2.9 10⁻⁹