KCET2022PhysicsElectrostatics
A charged particle of mass m and charge q is released from rest in an uniform electric field E. Neglecting the effect of gravity, the kinetic energy of the charged particle after t seconds is
Options
- AE q^2 m 2 t^2
- BE q m t
- CE^2 q^2 t^2 2 m
- D2 E^2 t^2 m q
Correct answer
C. E^2 q^2 t^2 2 m
Step-by-step solution
According to given situation, force on charge particle in uniform electric field, F=q E Acceleration of charge particle, a= F m = q E m Velocity of charge particle after time t is given as v=u+a t=0+ q E m t v= q E t m Kinetic energy of the charged particle K= 1 2 m v^2= 1 2 m ( q E t m )^2= E^2 q^2 t^2 2 m