A particle of mass ( m ) and charge ( q ) is placed at rest in uniform electric field ( E ) and then released. The kinetic energy attained by the particle after moving a distance ( y ) is

Step-by-step solution

(A) Velocity gained after moving a distance ( y ) is ( v²=u²+2 a y ) Here ( u =0 ) and ( a = q E m ) ( v²=2 ( q E m ) y ) Kinetic energy, ( E= 1 2 m v² ) ( = 1 2 m (2 q E m y ) ) ( E = qEy )