KCET2017PhysicsElectrostatics
A straight wire of length ( 50 ~cm ) carrying a current of ( 2.5 ~A ) is suspended in mid-air by a uniform magnetic field of ( 0.5 ~T ) (as shown in figure). The mass of the wire is ( ( g =10 ~m ~s ⁻² ) )
Options
- A( 62.5 gm )
- B( 250 gm )
- C( 125 gm )
- D( 100 gm )
Correct answer
A. ( 62.5 gm )
Step-by-step solution
Given, the wire is suspended in mid air by uniform magnetic field. Now, [ array l F=m g I B l=m g m= I B l g m= 2.5 0.5 (50 10⁻² ) 10 =0.625 ~kg =62.5 ~g array ] Thus, mass of wire is ( 62.5 ~g ).