KCET2016PhysicsElectrostatics
If there are only one type of charge in the universe, then ( ( E ) Electric field, ( d s ) Area vector ( ) )
Options
- A( E d_ S 0 ) on any surface
- B( E d s ) could not be defined
- C( E d s= ) if charge is inside
- D( E d s=0 ) if charge is outside, ( = q ₀ ) if charge is inside
Correct answer
D. ( E d s=0 ) if charge is outside, ( = q ₀ ) if charge is inside
Step-by-step solution
If there are only one type of charge in the universe, then by Gauss Law: if charge is outside the surface then charge enclosed by gaussian surface is zero. Therefore, ( E d s =0 ) If charge is inside the gaussian surface, then flux ( ) is given by ( E d s = q ₀ )